MATH SOLVE

3 months ago

Q:
# The relationship between two numbers is described below, where x represents the first number and y represents the second number. The square of the first number is equal to the sum of the second number and 16. The difference of 4 times the second number and 1 is equal to the first number multiplied by 7. Select the equations that form the system that models this situation. Then, select the solution(s) of the system. Equations Solutions y2 + 16 = x (2x)2 = y + 16 (1,15) (5,9) x2 = y + 16 7y - 1 = 4x (2,-12) (8,48) 1 - 4y = 7x 4y - 1 = 7x (4,-7) (9,3) NextReset

Accepted Solution

A:

Answer:[tex]x^2=y+16[/tex][tex]4y-1=7x[/tex]Step-by-step explanation:The condition says: The square of first number is equal to the sum of the second number and 16: Lets say that the first number is 'x' and the second number is 'y'. So the square of 'x' is [tex]x^2[/tex] and that is equal to the sum of second number i.e y and 16: [tex]x^2=y+16[/tex] Second condition says that: The difference of 4 times the second number and 1 is equal to the first number multiplied by 7: 4 times the second number is [tex]4y[/tex] and difference of 1 is: [tex]4y-1[/tex]and this is equal to 7 times the first number: Β [tex]7\times x[/tex][tex]4y-1=7x[/tex]So the two equations are: [tex]x^2=y+16[/tex][tex]4y-1=7x[/tex]