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Find the value of the lesser root of x^2-6x+8=0
4 months ago
Q:
Find the value of the lesser root of x^2-6x+8=0
Accepted Solution
A:
x² - 6x +8= 0,
[tex]x= \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} a=1, b=-6, c=8 [/tex]
[tex]x= \frac{6+/- \sqrt{36-4*1*8} }{2*1} x=(6+/- \sqrt{36-32} )/2 x=(6+/-2)/2 x_{1} =4, x_{2}=2[/tex]